Base | Representation |
---|---|
bin | 100100100111110010010… |
… | …0100001110001110110011 |
3 | 122211011200020200102121212 |
4 | 1021033210210032032303 |
5 | 1124431034244414324 |
6 | 14412123355110335 |
7 | 1026432262015331 |
oct | 111174444161663 |
9 | 18734606612555 |
10 | 5033241404339 |
11 | 1670649613655 |
12 | 6935864423ab |
13 | 2a682bb639a5 |
14 | 1358784b6b51 |
15 | 8add5bc670e |
hex | 493e490e3b3 |
5033241404339 has 2 divisors, whose sum is σ = 5033241404340. Its totient is φ = 5033241404338.
The previous prime is 5033241404291. The next prime is 5033241404363. The reversal of 5033241404339 is 9334041423305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5033241404339 - 28 = 5033241404083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5033241404296 and 5033241404305.
It is not a weakly prime, because it can be changed into another prime (5033241404539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516620702169 + 2516620702170.
It is an arithmetic number, because the mean of its divisors is an integer number (2516620702170).
Almost surely, 25033241404339 is an apocalyptic number.
5033241404339 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033241404339 is an equidigital number, since it uses as much as digits as its factorization.
5033241404339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 5033241404339 in words is "five trillion, thirty-three billion, two hundred forty-one million, four hundred four thousand, three hundred thirty-nine".
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