Base | Representation |
---|---|
bin | 101110111000000101… |
… | …110000001100100011 |
3 | 11210220210201020220211 |
4 | 232320011300030203 |
5 | 1311040241444011 |
6 | 35042302114551 |
7 | 3431205524266 |
oct | 567005601443 |
9 | 153823636824 |
10 | 50333156131 |
11 | 1a3898331a5 |
12 | 990857ba57 |
13 | 4991aa922b |
14 | 2616a94cdd |
15 | 1498c52b21 |
hex | bb8170323 |
50333156131 has 2 divisors, whose sum is σ = 50333156132. Its totient is φ = 50333156130.
The previous prime is 50333156099. The next prime is 50333156191. The reversal of 50333156131 is 13165133305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50333156131 - 25 = 50333156099 is a prime.
It is a super-2 number, since 2×503331561312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50333156093 and 50333156102.
It is not a weakly prime, because it can be changed into another prime (50333156191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25166578065 + 25166578066.
It is an arithmetic number, because the mean of its divisors is an integer number (25166578066).
Almost surely, 250333156131 is an apocalyptic number.
50333156131 is a deficient number, since it is larger than the sum of its proper divisors (1).
50333156131 is an equidigital number, since it uses as much as digits as its factorization.
50333156131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 50333156131 its reverse (13165133305), we get a palindrome (63498289436).
The spelling of 50333156131 in words is "fifty billion, three hundred thirty-three million, one hundred fifty-six thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •