Base | Representation |
---|---|
bin | 100100100111111011011… |
… | …0011100000110000000001 |
3 | 122211012110120110201211111 |
4 | 1021033312303200300001 |
5 | 1124432201113332431 |
6 | 14412214005443321 |
7 | 1026442665655441 |
oct | 111176663406001 |
9 | 18735416421744 |
10 | 5033547402241 |
11 | 1670796314386 |
12 | 693650a10541 |
13 | 2a687a381837 |
14 | 1358a6dac121 |
15 | 8ae029bc7b1 |
hex | 493f6ce0c01 |
5033547402241 has 2 divisors, whose sum is σ = 5033547402242. Its totient is φ = 5033547402240.
The previous prime is 5033547402227. The next prime is 5033547402251. The reversal of 5033547402241 is 1422047453305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3499593318400 + 1533954083841 = 1870720^2 + 1238529^2 .
It is a cyclic number.
It is not a de Polignac number, because 5033547402241 - 217 = 5033547271169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5033547402194 and 5033547402203.
It is not a weakly prime, because it can be changed into another prime (5033547402211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516773701120 + 2516773701121.
It is an arithmetic number, because the mean of its divisors is an integer number (2516773701121).
Almost surely, 25033547402241 is an apocalyptic number.
It is an amenable number.
5033547402241 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033547402241 is an equidigital number, since it uses as much as digits as its factorization.
5033547402241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 40.
The spelling of 5033547402241 in words is "five trillion, thirty-three billion, five hundred forty-seven million, four hundred two thousand, two hundred forty-one".
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