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5033547402241 is a prime number
BaseRepresentation
bin100100100111111011011…
…0011100000110000000001
3122211012110120110201211111
41021033312303200300001
51124432201113332431
614412214005443321
71026442665655441
oct111176663406001
918735416421744
105033547402241
111670796314386
12693650a10541
132a687a381837
141358a6dac121
158ae029bc7b1
hex493f6ce0c01

5033547402241 has 2 divisors, whose sum is σ = 5033547402242. Its totient is φ = 5033547402240.

The previous prime is 5033547402227. The next prime is 5033547402251. The reversal of 5033547402241 is 1422047453305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3499593318400 + 1533954083841 = 1870720^2 + 1238529^2 .

It is a cyclic number.

It is not a de Polignac number, because 5033547402241 - 217 = 5033547271169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5033547402194 and 5033547402203.

It is not a weakly prime, because it can be changed into another prime (5033547402211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516773701120 + 2516773701121.

It is an arithmetic number, because the mean of its divisors is an integer number (2516773701121).

Almost surely, 25033547402241 is an apocalyptic number.

It is an amenable number.

5033547402241 is a deficient number, since it is larger than the sum of its proper divisors (1).

5033547402241 is an equidigital number, since it uses as much as digits as its factorization.

5033547402241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 40.

The spelling of 5033547402241 in words is "five trillion, thirty-three billion, five hundred forty-seven million, four hundred two thousand, two hundred forty-one".