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50340416233 is a prime number
BaseRepresentation
bin101110111000100001…
…011100101011101001
311210221022101002220111
4232320201130223221
51311044121304413
635043121454321
73431324322622
oct567041345351
9153838332814
1050340416233
111a392941888
12990aaa13a1
13499344b953
142617a24a49
1514996d8d3d
hexbb885cae9

50340416233 has 2 divisors, whose sum is σ = 50340416234. Its totient is φ = 50340416232.

The previous prime is 50340416221. The next prime is 50340416251. The reversal of 50340416233 is 33261404305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49305314304 + 1035101929 = 222048^2 + 32173^2 .

It is a cyclic number.

It is not a de Polignac number, because 50340416233 - 217 = 50340285161 is a prime.

It is a super-3 number, since 3×503404162333 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50340416195 and 50340416204.

It is not a weakly prime, because it can be changed into another prime (50340416293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25170208116 + 25170208117.

It is an arithmetic number, because the mean of its divisors is an integer number (25170208117).

Almost surely, 250340416233 is an apocalyptic number.

It is an amenable number.

50340416233 is a deficient number, since it is larger than the sum of its proper divisors (1).

50340416233 is an equidigital number, since it uses as much as digits as its factorization.

50340416233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

The spelling of 50340416233 in words is "fifty billion, three hundred forty million, four hundred sixteen thousand, two hundred thirty-three".