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5034234041151 = 371132121463987
BaseRepresentation
bin100100101000001111110…
…1110110101001100111111
3122211021020102111121100020
41021100133232311030333
51124440102403304101
614412410054503223
71026466004211240
oct111203756651477
918737212447306
105034234041151
111671008968357
12693802964b13
132a69596c3553
14135930268cc7
158ae42e01136
hex4941fbb533f

5034234041151 has 16 divisors (see below), whose sum is σ = 7739100628224. Its totient is φ = 2851247597184.

The previous prime is 5034234041141. The next prime is 5034234041197. The reversal of 5034234041151 is 1511404324305.

It is not a de Polignac number, because 5034234041151 - 210 = 5034234040127 is a prime.

It is a super-2 number, since 2×50342340411512 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5034234041141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1060729621 + ... + 1060734366.

It is an arithmetic number, because the mean of its divisors is an integer number (483693789264).

Almost surely, 25034234041151 is an apocalyptic number.

5034234041151 is a deficient number, since it is larger than the sum of its proper divisors (2704866587073).

5034234041151 is a wasteful number, since it uses less digits than its factorization.

5034234041151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2121464110.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5034234041151 its reverse (1511404324305), we get a palindrome (6545638365456).

The spelling of 5034234041151 in words is "five trillion, thirty-four billion, two hundred thirty-four million, forty-one thousand, one hundred fifty-one".

Divisors: 1 3 7 21 113 339 791 2373 2121463987 6364391961 14850247909 44550743727 239725430531 719176291593 1678078013717 5034234041151