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5034234041197 is a prime number
BaseRepresentation
bin100100101000001111110…
…1110110101001101101101
3122211021020102111121101221
41021100133232311031231
51124440102403304242
614412410054503341
71026466004211334
oct111203756651555
918737212447357
105034234041197
111671008968399
12693802964b51
132a69596c358a
14135930268d1b
158ae42e01167
hex4941fbb536d

5034234041197 has 2 divisors, whose sum is σ = 5034234041198. Its totient is φ = 5034234041196.

The previous prime is 5034234041141. The next prime is 5034234041203. The reversal of 5034234041197 is 7911404324305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3345848255556 + 1688385785641 = 1829166^2 + 1299379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5034234041197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5034234041797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517117020598 + 2517117020599.

It is an arithmetic number, because the mean of its divisors is an integer number (2517117020599).

Almost surely, 25034234041197 is an apocalyptic number.

It is an amenable number.

5034234041197 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034234041197 is an equidigital number, since it uses as much as digits as its factorization.

5034234041197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 5034234041197 in words is "five trillion, thirty-four billion, two hundred thirty-four million, forty-one thousand, one hundred ninety-seven".