Base | Representation |
---|---|
bin | 10110111001001001111100… |
… | …01100111011111011100011 |
3 | 20121020200102021222011212112 |
4 | 23130210332030323323203 |
5 | 23044302120421130021 |
6 | 255022543030345535 |
7 | 13414054331161121 |
oct | 1334447614737343 |
9 | 217220367864775 |
10 | 50342355255011 |
11 | 1504a089134376 |
12 | 5790828abb2ab |
13 | 2212357554551 |
14 | c60823a4a911 |
15 | 5c47c098dd5b |
hex | 2dc93e33bee3 |
50342355255011 has 2 divisors, whose sum is σ = 50342355255012. Its totient is φ = 50342355255010.
The previous prime is 50342355254977. The next prime is 50342355255047. The reversal of 50342355255011 is 11055255324305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50342355255011 is a prime.
It is a super-2 number, since 2×503423552550112 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 50342355255011.
It is not a weakly prime, because it can be changed into another prime (50342355255061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171177627505 + 25171177627506.
It is an arithmetic number, because the mean of its divisors is an integer number (25171177627506).
Almost surely, 250342355255011 is an apocalyptic number.
50342355255011 is a deficient number, since it is larger than the sum of its proper divisors (1).
50342355255011 is an equidigital number, since it uses as much as digits as its factorization.
50342355255011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 50342355255011 in words is "fifty trillion, three hundred forty-two billion, three hundred fifty-five million, two hundred fifty-five thousand, eleven".
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