Base | Representation |
---|---|
bin | 100100101000011110011… |
… | …0010110101100110111011 |
3 | 122211022111101222201101121 |
4 | 1021100330302311212323 |
5 | 1124442102214140101 |
6 | 14412530313330111 |
7 | 1026514044516046 |
oct | 111207462654673 |
9 | 18738441881347 |
10 | 5034721630651 |
11 | 1671239118589 |
12 | 69391a106937 |
13 | 2a6a0672184b |
14 | 135978d0dc5d |
15 | 8ae70b170a1 |
hex | 4943ccb59bb |
5034721630651 has 2 divisors, whose sum is σ = 5034721630652. Its totient is φ = 5034721630650.
The previous prime is 5034721630621. The next prime is 5034721630661. The reversal of 5034721630651 is 1560361274305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5034721630651 - 213 = 5034721622459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5034721630598 and 5034721630607.
It is not a weakly prime, because it can be changed into another prime (5034721630621) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517360815325 + 2517360815326.
It is an arithmetic number, because the mean of its divisors is an integer number (2517360815326).
Almost surely, 25034721630651 is an apocalyptic number.
5034721630651 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034721630651 is an equidigital number, since it uses as much as digits as its factorization.
5034721630651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 43.
The spelling of 5034721630651 in words is "five trillion, thirty-four billion, seven hundred twenty-one million, six hundred thirty thousand, six hundred fifty-one".
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