Base | Representation |
---|---|
bin | 101110111001001010… |
… | …111101111000110011 |
3 | 11210222001212001211102 |
4 | 232321022331320303 |
5 | 1311104413101042 |
6 | 35044151035015 |
7 | 3431515663301 |
oct | 567112757063 |
9 | 153861761742 |
10 | 50351300147 |
11 | 1a398aa6055 |
12 | 991266ba6b |
13 | 499578c935 |
14 | 2619259271 |
15 | 149a638b32 |
hex | bb92bde33 |
50351300147 has 2 divisors, whose sum is σ = 50351300148. Its totient is φ = 50351300146.
The previous prime is 50351300107. The next prime is 50351300171. The reversal of 50351300147 is 74100315305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50351300147 - 228 = 50082864691 is a prime.
It is not a weakly prime, because it can be changed into another prime (50351300107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25175650073 + 25175650074.
It is an arithmetic number, because the mean of its divisors is an integer number (25175650074).
Almost surely, 250351300147 is an apocalyptic number.
50351300147 is a deficient number, since it is larger than the sum of its proper divisors (1).
50351300147 is an equidigital number, since it uses as much as digits as its factorization.
50351300147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 29.
The spelling of 50351300147 in words is "fifty billion, three hundred fifty-one million, three hundred thousand, one hundred forty-seven".
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