Base | Representation |
---|---|
bin | 100100101000101101101… |
… | …0110100100100011001011 |
3 | 122211100211010200202100012 |
4 | 1021101123112210203023 |
5 | 1124444124441030233 |
6 | 14413053230102135 |
7 | 1026532541331014 |
oct | 111213326444313 |
9 | 18740733622305 |
10 | 5035234314443 |
11 | 16714815584a3 |
12 | 693a4194a94b |
13 | 2a6a889c7c38 |
14 | 1359c704800b |
15 | 8aea0b38548 |
hex | 4945b5a48cb |
5035234314443 has 2 divisors, whose sum is σ = 5035234314444. Its totient is φ = 5035234314442.
The previous prime is 5035234314437. The next prime is 5035234314493. The reversal of 5035234314443 is 3444134325305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5035234314443 - 210 = 5035234313419 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5035234314443.
It is not a weakly prime, because it can be changed into another prime (5035234314493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517617157221 + 2517617157222.
It is an arithmetic number, because the mean of its divisors is an integer number (2517617157222).
Almost surely, 25035234314443 is an apocalyptic number.
5035234314443 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035234314443 is an equidigital number, since it uses as much as digits as its factorization.
5035234314443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 41.
Adding to 5035234314443 its reverse (3444134325305), we get a palindrome (8479368639748).
The spelling of 5035234314443 in words is "five trillion, thirty-five billion, two hundred thirty-four million, three hundred fourteen thousand, four hundred forty-three".
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