Base | Representation |
---|---|
bin | 1001011000010001… |
… | …11010001001100011 |
3 | 110222221011220120212 |
4 | 10230020322021203 |
5 | 40303042001011 |
6 | 2151400124335 |
7 | 235533021254 |
oct | 45410721143 |
9 | 13887156525 |
10 | 5035500131 |
11 | 2154454862 |
12 | b864666ab |
13 | 62330b19c |
14 | 35aaa2b2b |
15 | 1e711a08b |
hex | 12c23a263 |
5035500131 has 2 divisors, whose sum is σ = 5035500132. Its totient is φ = 5035500130.
The previous prime is 5035500121. The next prime is 5035500167. The reversal of 5035500131 is 1310055305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5035500131 - 222 = 5031305827 is a prime.
It is a super-2 number, since 2×50355001312 = 50712523138602034322, which contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 5035500097 and 5035500106.
It is not a weakly prime, because it can be changed into another prime (5035500121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517750065 + 2517750066.
It is an arithmetic number, because the mean of its divisors is an integer number (2517750066).
Almost surely, 25035500131 is an apocalyptic number.
5035500131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035500131 is an equidigital number, since it uses as much as digits as its factorization.
5035500131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1125, while the sum is 23.
The square root of 5035500131 is about 70961.2579581281. The cubic root of 5035500131 is about 1714.0133644498.
Adding to 5035500131 its reverse (1310055305), we get a palindrome (6345555436).
The spelling of 5035500131 in words is "five billion, thirty-five million, five hundred thousand, one hundred thirty-one".
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