Base | Representation |
---|---|
bin | 101110111010111101… |
… | …000110100001010011 |
3 | 11211001011011011001021 |
4 | 232322331012201103 |
5 | 1311140043014143 |
6 | 35051140220311 |
7 | 3432331206046 |
oct | 567275064123 |
9 | 154034134037 |
10 | 50381219923 |
11 | 1a403981241 |
12 | 992069a697 |
13 | 499ba37248 |
14 | 261d206c5d |
15 | 149d098ced |
hex | bbaf46853 |
50381219923 has 2 divisors, whose sum is σ = 50381219924. Its totient is φ = 50381219922.
The previous prime is 50381219897. The next prime is 50381219971. The reversal of 50381219923 is 32991218305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50381219923 - 213 = 50381211731 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50381219923.
It is not a weakly prime, because it can be changed into another prime (50381219123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25190609961 + 25190609962.
It is an arithmetic number, because the mean of its divisors is an integer number (25190609962).
Almost surely, 250381219923 is an apocalyptic number.
50381219923 is a deficient number, since it is larger than the sum of its proper divisors (1).
50381219923 is an equidigital number, since it uses as much as digits as its factorization.
50381219923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 43.
The spelling of 50381219923 in words is "fifty billion, three hundred eighty-one million, two hundred nineteen thousand, nine hundred twenty-three".
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