504000113 has 2 divisors, whose sum is σ = 504000114. Its totient is φ = 504000112.

The previous prime is 504000089. The next prime is 504000131. The reversal of 504000113 is 311000405.

Together with next prime (504000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252555664 + 251444449 = 15892^2 + 15857^2 .

It is a cyclic number.

It is not a de Polignac number, because 504000113 - 2²² = 499805809 is a prime.

It is a super-2 number, since 2×504000113² = 508032227808025538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (504000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252000056 + 252000057.

It is an arithmetic number, because the mean of its divisors is an integer number (252000057).

Almost surely, 2^504000113 is an apocalyptic number.

It is an amenable number.

504000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

504000113 is an equidigital number, since it uses as much as digits as its factorization.

504000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 504000113 is about 22449.9468373535. The cubic root of 504000113 is about 795.8115010546.

Adding to 504000113 its reverse (311000405), we get a palindrome (815000518).

The spelling of 504000113 in words is "five hundred four million, one hundred thirteen", and thus it is an aban number.