Base | Representation |
---|---|
bin | 101110111100001001… |
… | …011111111110101011 |
3 | 11211002112211122020022 |
4 | 232330021133332223 |
5 | 1311210204402042 |
6 | 35053133351055 |
7 | 3432663350336 |
oct | 567411377653 |
9 | 154075748208 |
10 | 50401247147 |
11 | 1a41420aa69 |
12 | 992733848b |
13 | 49a2c29b84 |
14 | 2621b3b61d |
15 | 149ec02cd2 |
hex | bbc25ffab |
50401247147 has 2 divisors, whose sum is σ = 50401247148. Its totient is φ = 50401247146.
The previous prime is 50401247129. The next prime is 50401247177. The reversal of 50401247147 is 74174210405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50401247147 - 28 = 50401246891 is a prime.
It is not a weakly prime, because it can be changed into another prime (50401247107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25200623573 + 25200623574.
It is an arithmetic number, because the mean of its divisors is an integer number (25200623574).
Almost surely, 250401247147 is an apocalyptic number.
50401247147 is a deficient number, since it is larger than the sum of its proper divisors (1).
50401247147 is an equidigital number, since it uses as much as digits as its factorization.
50401247147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31360, while the sum is 35.
The spelling of 50401247147 in words is "fifty billion, four hundred one million, two hundred forty-seven thousand, one hundred forty-seven".
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