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5040130041412 = 221260032510353
BaseRepresentation
bin100100101010111111100…
…1010010010011001000100
3122211211110022212110012021
41021111333022102121010
51130034141242311122
614415223114332524
71030065056325334
oct111257712223104
918754408773167
105040130041412
111673564015644
1269498942a144
132a73890780bb
14135d2d3250c4
158b18a8441c7
hex4957f292644

5040130041412 has 6 divisors (see below), whose sum is σ = 8820227572478. Its totient is φ = 2520065020704.

The previous prime is 5040130041409. The next prime is 5040130041449. The reversal of 5040130041412 is 2141400310405.

It can be written as a sum of positive squares in only one way, i.e., 2611662852096 + 2428467189316 = 1616064^2 + 1558354^2 .

It is a super-3 number, since 3×50401300414123 (a number of 39 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630016255173 + ... + 630016255180.

Almost surely, 25040130041412 is an apocalyptic number.

It is an amenable number.

5040130041412 is a deficient number, since it is larger than the sum of its proper divisors (3780097531066).

5040130041412 is a wasteful number, since it uses less digits than its factorization.

5040130041412 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1260032510357 (or 1260032510355 counting only the distinct ones).

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 5040130041412 its reverse (2141400310405), we get a palindrome (7181530351817).

The spelling of 5040130041412 in words is "five trillion, forty billion, one hundred thirty million, forty-one thousand, four hundred twelve".

Divisors: 1 2 4 1260032510353 2520065020706 5040130041412