Base | Representation |
---|---|
bin | 100100101010111111100… |
… | …1010010010011001000100 |
3 | 122211211110022212110012021 |
4 | 1021111333022102121010 |
5 | 1130034141242311122 |
6 | 14415223114332524 |
7 | 1030065056325334 |
oct | 111257712223104 |
9 | 18754408773167 |
10 | 5040130041412 |
11 | 1673564015644 |
12 | 69498942a144 |
13 | 2a73890780bb |
14 | 135d2d3250c4 |
15 | 8b18a8441c7 |
hex | 4957f292644 |
5040130041412 has 6 divisors (see below), whose sum is σ = 8820227572478. Its totient is φ = 2520065020704.
The previous prime is 5040130041409. The next prime is 5040130041449. The reversal of 5040130041412 is 2141400310405.
It can be written as a sum of positive squares in only one way, i.e., 2611662852096 + 2428467189316 = 1616064^2 + 1558354^2 .
It is a super-3 number, since 3×50401300414123 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630016255173 + ... + 630016255180.
Almost surely, 25040130041412 is an apocalyptic number.
It is an amenable number.
5040130041412 is a deficient number, since it is larger than the sum of its proper divisors (3780097531066).
5040130041412 is a wasteful number, since it uses less digits than its factorization.
5040130041412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1260032510357 (or 1260032510355 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 5040130041412 its reverse (2141400310405), we get a palindrome (7181530351817).
The spelling of 5040130041412 in words is "five trillion, forty billion, one hundred thirty million, forty-one thousand, four hundred twelve".
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