Search a number
-
+
5040278993 = 49727101359
BaseRepresentation
bin1001011000110110…
…01000110111010001
3111000021011200221202
410230123020313101
540310302411433
62152050400545
7235621443641
oct45433106721
914007150852
105040278993
112157119232
12b87b90155
136242c2409
1435b588521
151e7760ee8
hex12c6c8dd1

5040278993 has 4 divisors (see below), whose sum is σ = 5040430080. Its totient is φ = 5040127908.

The previous prime is 5040278989. The next prime is 5040279011. The reversal of 5040278993 is 3998720405.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3998720405 = 5799744081.

It is a cyclic number.

It is not a de Polignac number, because 5040278993 - 22 = 5040278989 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5040278923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 953 + ... + 100406.

It is an arithmetic number, because the mean of its divisors is an integer number (1260107520).

Almost surely, 25040278993 is an apocalyptic number.

It is an amenable number.

5040278993 is a deficient number, since it is larger than the sum of its proper divisors (151087).

5040278993 is a wasteful number, since it uses less digits than its factorization.

5040278993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151086.

The product of its (nonzero) digits is 544320, while the sum is 47.

The square root of 5040278993 is about 70994.9223043451. The cubic root of 5040278993 is about 1714.5554121311. Note that the first 3 decimals are identical.

The spelling of 5040278993 in words is "five billion, forty million, two hundred seventy-eight thousand, nine hundred ninety-three".

Divisors: 1 49727 101359 5040278993