Base | Representation |
---|---|
bin | 100100101011000101000… |
… | …1000100010111100100111 |
3 | 122211211221011021100011210 |
4 | 1021112022020202330213 |
5 | 1130040030404244221 |
6 | 14415253252202503 |
7 | 1030102453151331 |
oct | 111261210427447 |
9 | 18754834240153 |
10 | 5040314134311 |
11 | 1673648a23335 |
12 | 694a1b009433 |
13 | 2a73b8252c01 |
14 | 135d49966451 |
15 | 8b19baaa276 |
hex | 4958a222f27 |
5040314134311 has 16 divisors (see below), whose sum is σ = 6864952155264. Its totient is φ = 3288699487584.
The previous prime is 5040314134307. The next prime is 5040314134313. The reversal of 5040314134311 is 1134314130405.
It is not a de Polignac number, because 5040314134311 - 22 = 5040314134307 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5040314134313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94563196 + ... + 94616481.
It is an arithmetic number, because the mean of its divisors is an integer number (429059509704).
Almost surely, 25040314134311 is an apocalyptic number.
5040314134311 is a deficient number, since it is larger than the sum of its proper divisors (1824638020953).
5040314134311 is a wasteful number, since it uses less digits than its factorization.
5040314134311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 189179870.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 5040314134311 its reverse (1134314130405), we get a palindrome (6174628264716).
The spelling of 5040314134311 in words is "five trillion, forty billion, three hundred fourteen million, one hundred thirty-four thousand, three hundred eleven".
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