Base | Representation |
---|---|
bin | 100100101011000101000… |
… | …1011111110100110010011 |
3 | 122211211221012222001022201 |
4 | 1021112022023332212103 |
5 | 1130040031122042003 |
6 | 14415253323344031 |
7 | 1030102463616334 |
oct | 111261213764623 |
9 | 18754835861281 |
10 | 5040315034003 |
11 | 1673649488287 |
12 | 694a1b382017 |
13 | 2a73b84a9582 |
14 | 135d49b1c28b |
15 | 8b19bbd6b1d |
hex | 4958a2fe993 |
5040315034003 has 2 divisors, whose sum is σ = 5040315034004. Its totient is φ = 5040315034002.
The previous prime is 5040315033991. The next prime is 5040315034021. The reversal of 5040315034003 is 3004305130405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5040315034003 - 29 = 5040315033491 is a prime.
It is not a weakly prime, because it can be changed into another prime (5040315034043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520157517001 + 2520157517002.
It is an arithmetic number, because the mean of its divisors is an integer number (2520157517002).
Almost surely, 25040315034003 is an apocalyptic number.
5040315034003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5040315034003 is an equidigital number, since it uses as much as digits as its factorization.
5040315034003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 28.
The spelling of 5040315034003 in words is "five trillion, forty billion, three hundred fifteen million, thirty-four thousand, three".
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