5040441204343 has 4 divisors (see below), whose sum is σ = 5069576702808. Its totient is φ = 5011305705880.

The previous prime is 5040441204319. The next prime is 5040441204347. The reversal of 5040441204343 is 3434021440405.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5040441204343 - 2¹³ = 5040441196151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5040441204299 and 5040441204308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5040441204347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14567748973 + ... + 14567749318.

It is an arithmetic number, because the mean of its divisors is an integer number (1267394175702).

Almost surely, 2^{5040441204343} is an apocalyptic number.

5040441204343 is a deficient number, since it is larger than the sum of its proper divisors (29135498465).

5040441204343 is a wasteful number, since it uses less digits than its factorization.

5040441204343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29135498464.

The product of its (nonzero) digits is 92160, while the sum is 34.

Adding to 5040441204343 its reverse (3434021440405), we get a palindrome (8474462644748).

The spelling of 5040441204343 in words is "five trillion, forty billion, four hundred forty-one million, two hundred four thousand, three hundred forty-three".