Base | Representation |
---|---|
bin | 1110101011000001000… |
… | …11101111010010011001 |
3 | 1210012020202201010122212 |
4 | 13111200203233102121 |
5 | 31224430033430342 |
6 | 1023332240124505 |
7 | 51264561054323 |
oct | 7254043572231 |
9 | 1705222633585 |
10 | 504131155097 |
11 | 184889992469 |
12 | 81854606735 |
13 | 38701ca094b |
14 | 1a585b58613 |
15 | d1a8664182 |
hex | 75608ef499 |
504131155097 has 2 divisors, whose sum is σ = 504131155098. Its totient is φ = 504131155096.
The previous prime is 504131155081. The next prime is 504131155141. The reversal of 504131155097 is 790551131405.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 267277626121 + 236853528976 = 516989^2 + 486676^2 .
It is a cyclic number.
It is not a de Polignac number, because 504131155097 - 24 = 504131155081 is a prime.
It is not a weakly prime, because it can be changed into another prime (504131155027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252065577548 + 252065577549.
It is an arithmetic number, because the mean of its divisors is an integer number (252065577549).
Almost surely, 2504131155097 is an apocalyptic number.
It is an amenable number.
504131155097 is a deficient number, since it is larger than the sum of its proper divisors (1).
504131155097 is an equidigital number, since it uses as much as digits as its factorization.
504131155097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94500, while the sum is 41.
The spelling of 504131155097 in words is "five hundred four billion, one hundred thirty-one million, one hundred fifty-five thousand, ninety-seven".
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