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50413115551 = 71710043881
BaseRepresentation
bin101110111100110110…
…110001100010011111
311211010101011121121211
4232330312301202133
51311221224144201
635054240005251
73433166261161
oct567466614237
9154111147554
1050413115551
111a41a986967
12992b300827
1349a5523cb6
14262354a931
1514a0c99651
hexbbcdb189f

50413115551 has 4 divisors (see below), whose sum is σ = 51123159504. Its totient is φ = 49703071600.

The previous prime is 50413115531. The next prime is 50413115573. The reversal of 50413115551 is 15551131405.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15551131405 = 53110226281.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50413115551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50413115521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355021870 + ... + 355022011.

It is an arithmetic number, because the mean of its divisors is an integer number (12780789876).

Almost surely, 250413115551 is an apocalyptic number.

50413115551 is a deficient number, since it is larger than the sum of its proper divisors (710043953).

50413115551 is an equidigital number, since it uses as much as digits as its factorization.

50413115551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710043952.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 50413115551 its reverse (15551131405), we get a palindrome (65964246956).

The spelling of 50413115551 in words is "fifty billion, four hundred thirteen million, one hundred fifteen thousand, five hundred fifty-one".

Divisors: 1 71 710043881 50413115551