Base | Representation |
---|---|
bin | 1110101011000001011… |
… | …10101101111001101001 |
3 | 1210012020222010100101220 |
4 | 13111200232231321221 |
5 | 31224431303024001 |
6 | 1023332421532253 |
7 | 51264624401604 |
oct | 7254056557151 |
9 | 1705228110356 |
10 | 504134033001 |
11 | 1848905786a5 |
12 | 81855574089 |
13 | 3870276a851 |
14 | 1a5862a733b |
15 | d1a8a31c36 |
hex | 7560bade69 |
504134033001 has 4 divisors (see below), whose sum is σ = 672178710672. Its totient is φ = 336089355332.
The previous prime is 504134032973. The next prime is 504134033047. The reversal of 504134033001 is 100330431405.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 504134033001 - 215 = 504134000233 is a prime.
It is a super-2 number, since 2×5041340330012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (504134031001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84022338831 + ... + 84022338836.
It is an arithmetic number, because the mean of its divisors is an integer number (168044677668).
Almost surely, 2504134033001 is an apocalyptic number.
It is an amenable number.
504134033001 is a deficient number, since it is larger than the sum of its proper divisors (168044677671).
504134033001 is a wasteful number, since it uses less digits than its factorization.
504134033001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168044677670.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 504134033001 its reverse (100330431405), we get a palindrome (604464464406).
The spelling of 504134033001 in words is "five hundred four billion, one hundred thirty-four million, thirty-three thousand, one".
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