Base | Representation |
---|---|
bin | 10110111011110001100011… |
… | …10001101111001000110111 |
3 | 20121120021200120020022112121 |
4 | 23131320301301233020313 |
5 | 23102240413311030401 |
6 | 255132144143500411 |
7 | 13423421266266403 |
oct | 1335706161571067 |
9 | 217507616208477 |
10 | 50432341111351 |
11 | 15084265875091 |
12 | 57a6160bb7707 |
13 | 221a998463ba4 |
14 | c64d1cb06103 |
15 | 5c6cda974ca1 |
hex | 2dde31c6f237 |
50432341111351 has 4 divisors (see below), whose sum is σ = 52171387356600. Its totient is φ = 48693294866104.
The previous prime is 50432341111343. The next prime is 50432341111363. The reversal of 50432341111351 is 15311114323405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50432341111351 - 23 = 50432341111343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50432341111391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 869523122581 + ... + 869523122638.
It is an arithmetic number, because the mean of its divisors is an integer number (13042846839150).
Almost surely, 250432341111351 is an apocalyptic number.
50432341111351 is a deficient number, since it is larger than the sum of its proper divisors (1739046245249).
50432341111351 is a wasteful number, since it uses less digits than its factorization.
50432341111351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1739046245248.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 50432341111351 its reverse (15311114323405), we get a palindrome (65743455434756).
The spelling of 50432341111351 in words is "fifty trillion, four hundred thirty-two billion, three hundred forty-one million, one hundred eleven thousand, three hundred fifty-one".
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