Base | Representation |
---|---|
bin | 111001010101100000111000… |
… | …0101110100110011111111101 |
3 | 2110010200212112201202100022111 |
4 | 1302223001300232212133331 |
5 | 1012101002300020430023 |
6 | 4544343522403214021 |
7 | 211141636630026454 |
oct | 16253016056463775 |
9 | 2403625481670274 |
10 | 504334131030013 |
11 | 1367729a4003759 |
12 | 48693400077311 |
13 | 1885467349106b |
14 | 8c77c8b847b9b |
15 | 3d48d4c69a00d |
hex | 1cab070ba67fd |
504334131030013 has 4 divisors (see below), whose sum is σ = 513849869351388. Its totient is φ = 494818392708640.
The previous prime is 504334131030001. The next prime is 504334131030019. The reversal of 504334131030013 is 310030131433405.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 272409314299929 + 231924816730084 = 16504827^2 + 15229078^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-504334131030013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (504334131030019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4757869160608 + ... + 4757869160713.
It is an arithmetic number, because the mean of its divisors is an integer number (128462467337847).
Almost surely, 2504334131030013 is an apocalyptic number.
504334131030013 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
504334131030013 is a deficient number, since it is larger than the sum of its proper divisors (9515738321375).
504334131030013 is an equidigital number, since it uses as much as digits as its factorization.
504334131030013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9515738321374.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 504334131030013 its reverse (310030131433405), we get a palindrome (814364262463418).
The spelling of 504334131030013 in words is "five hundred four trillion, three hundred thirty-four billion, one hundred thirty-one million, thirty thousand, thirteen".
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