Base | Representation |
---|---|
bin | 101110111110100011… |
… | …110111011100011001 |
3 | 11211012100222112112122 |
4 | 232332203313130121 |
5 | 1311301034312213 |
6 | 35101140551025 |
7 | 3433664330006 |
oct | 567643673431 |
9 | 154170875478 |
10 | 50441713433 |
11 | 1a435039981 |
12 | 99389b2475 |
13 | 49ab427a17 |
14 | 26272728ad |
15 | 14a3547d08 |
hex | bbe8f7719 |
50441713433 has 2 divisors, whose sum is σ = 50441713434. Its totient is φ = 50441713432.
The previous prime is 50441713423. The next prime is 50441713447. The reversal of 50441713433 is 33431714405.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29748315529 + 20693397904 = 172477^2 + 143852^2 .
It is a cyclic number.
It is not a de Polignac number, because 50441713433 - 224 = 50424936217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50441713393 and 50441713402.
It is not a weakly prime, because it can be changed into another prime (50441713423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25220856716 + 25220856717.
It is an arithmetic number, because the mean of its divisors is an integer number (25220856717).
Almost surely, 250441713433 is an apocalyptic number.
It is an amenable number.
50441713433 is a deficient number, since it is larger than the sum of its proper divisors (1).
50441713433 is an equidigital number, since it uses as much as digits as its factorization.
50441713433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 35.
The spelling of 50441713433 in words is "fifty billion, four hundred forty-one million, seven hundred thirteen thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •