Base | Representation |
---|---|
bin | 1110101011111101111… |
… | …00011111010110101001 |
3 | 1210020120021222220101201 |
4 | 13111332330133112221 |
5 | 31232001041204123 |
6 | 1023455011044201 |
7 | 51313321245616 |
oct | 7257674372651 |
9 | 1706507886351 |
10 | 504640959913 |
11 | 185020736362 |
12 | 819772a0661 |
13 | 387837a97bc |
14 | 1a5d374350d |
15 | d1d82b75ad |
hex | 757ef1f5a9 |
504640959913 has 2 divisors, whose sum is σ = 504640959914. Its totient is φ = 504640959912.
The previous prime is 504640959869. The next prime is 504640959929. The reversal of 504640959913 is 319959046405.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 400096731024 + 104544228889 = 632532^2 + 323333^2 .
It is a cyclic number.
It is not a de Polignac number, because 504640959913 - 29 = 504640959401 is a prime.
It is not a weakly prime, because it can be changed into another prime (504640959943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252320479956 + 252320479957.
It is an arithmetic number, because the mean of its divisors is an integer number (252320479957).
Almost surely, 2504640959913 is an apocalyptic number.
It is an amenable number.
504640959913 is a deficient number, since it is larger than the sum of its proper divisors (1).
504640959913 is an equidigital number, since it uses as much as digits as its factorization.
504640959913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5248800, while the sum is 55.
The spelling of 504640959913 in words is "five hundred four billion, six hundred forty million, nine hundred fifty-nine thousand, nine hundred thirteen".
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