Base | Representation |
---|---|
bin | 10110111100111111111010… |
… | …00111000001000000110001 |
3 | 20121201022021012221111211101 |
4 | 23132133331013001000301 |
5 | 23103433041213420342 |
6 | 255203342245244401 |
7 | 13426440602012161 |
oct | 1336377507010061 |
9 | 217638235844741 |
10 | 50474407170097 |
11 | 150a0091a89699 |
12 | 57b2340a03701 |
13 | 222194057c401 |
14 | c66d8d8465a1 |
15 | 5c7e4da1c3b7 |
hex | 2de7fd1c1031 |
50474407170097 has 2 divisors, whose sum is σ = 50474407170098. Its totient is φ = 50474407170096.
The previous prime is 50474407169999. The next prime is 50474407170107. The reversal of 50474407170097 is 79007170447405.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49928299472016 + 546107698081 = 7065996^2 + 738991^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50474407170097 is a prime.
It is not a weakly prime, because it can be changed into another prime (50474407170197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25237203585048 + 25237203585049.
It is an arithmetic number, because the mean of its divisors is an integer number (25237203585049).
Almost surely, 250474407170097 is an apocalyptic number.
It is an amenable number.
50474407170097 is a deficient number, since it is larger than the sum of its proper divisors (1).
50474407170097 is an equidigital number, since it uses as much as digits as its factorization.
50474407170097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6914880, while the sum is 55.
The spelling of 50474407170097 in words is "fifty trillion, four hundred seventy-four billion, four hundred seven million, one hundred seventy thousand, ninety-seven".
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