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505010034613153 is a prime number
BaseRepresentation
bin111001011010011011100111…
…1101110001001101110100001
32110020002111011121120221021201
41302310313033232021232201
51012143041022330110103
64550022223534521201
7211241525303503006
oct16264671756115641
92406074147527251
10505010034613153
11136a03609a55753
12487823b2966201
13188a331b674074
148c9c88a7b58ad
153d5b70b06851d
hex1cb4dcfb89ba1

505010034613153 has 2 divisors, whose sum is σ = 505010034613154. Its totient is φ = 505010034613152.

The previous prime is 505010034613067. The next prime is 505010034613159. The reversal of 505010034613153 is 351316430010505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 403528426992289 + 101481607620864 = 20088017^2 + 10073808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-505010034613153 is a prime.

It is a super-2 number, since 2×5050100346131532 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (505010034613159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252505017306576 + 252505017306577.

It is an arithmetic number, because the mean of its divisors is an integer number (252505017306577).

Almost surely, 2505010034613153 is an apocalyptic number.

It is an amenable number.

505010034613153 is a deficient number, since it is larger than the sum of its proper divisors (1).

505010034613153 is an equidigital number, since it uses as much as digits as its factorization.

505010034613153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 505010034613153 its reverse (351316430010505), we get a palindrome (856326464623658).

The spelling of 505010034613153 in words is "five hundred five trillion, ten billion, thirty-four million, six hundred thirteen thousand, one hundred fifty-three".