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50504211331 = 77214887333
BaseRepresentation
bin101111000010010010…
…010001101110000011
311211100201120202112121
4233002102101232003
51311413034230311
635111252305111
73435353466430
oct570222215603
9154321522477
1050504211331
111a467346532
129955912197
1349bb36a922
1426316a0b87
1514a8c90b71
hexbc2491b83

50504211331 has 4 divisors (see below), whose sum is σ = 57719098672. Its totient is φ = 43289323992.

The previous prime is 50504211323. The next prime is 50504211377. The reversal of 50504211331 is 13311240505.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50504211331 - 23 = 50504211323 is a prime.

It is a super-2 number, since 2×505042113312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50504211296 and 50504211305.

It is not an unprimeable number, because it can be changed into a prime (50504211311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3607443660 + ... + 3607443673.

It is an arithmetic number, because the mean of its divisors is an integer number (14429774668).

Almost surely, 250504211331 is an apocalyptic number.

50504211331 is a deficient number, since it is larger than the sum of its proper divisors (7214887341).

50504211331 is an equidigital number, since it uses as much as digits as its factorization.

50504211331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7214887340.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 50504211331 its reverse (13311240505), we get a palindrome (63815451836).

The spelling of 50504211331 in words is "fifty billion, five hundred four million, two hundred eleven thousand, three hundred thirty-one".

Divisors: 1 7 7214887333 50504211331