Base | Representation |
---|---|
bin | 10110111101111001110100… |
… | …11010110110010100000011 |
3 | 20121211021112011121220000101 |
4 | 23132330322122312110003 |
5 | 23104440231120103103 |
6 | 255225523500303231 |
7 | 13431621246253543 |
oct | 1336747232662403 |
9 | 217737464556011 |
10 | 50505500550403 |
11 | 15102298426508 |
12 | 57b8379b41b17 |
13 | 22248573180b2 |
14 | c6869d189323 |
15 | 5c8b6d620a1d |
hex | 2def3a6b6503 |
50505500550403 has 2 divisors, whose sum is σ = 50505500550404. Its totient is φ = 50505500550402.
The previous prime is 50505500550359. The next prime is 50505500550521. The reversal of 50505500550403 is 30405500550505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50505500550403 - 229 = 50504963679491 is a prime.
It is not a weakly prime, because it can be changed into another prime (50505500551403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25252750275201 + 25252750275202.
It is an arithmetic number, because the mean of its divisors is an integer number (25252750275202).
Almost surely, 250505500550403 is an apocalyptic number.
50505500550403 is a deficient number, since it is larger than the sum of its proper divisors (1).
50505500550403 is an equidigital number, since it uses as much as digits as its factorization.
50505500550403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 187500, while the sum is 37.
The spelling of 50505500550403 in words is "fifty trillion, five hundred five billion, five hundred million, five hundred fifty thousand, four hundred three".
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