5050555551403 has 2 divisors, whose sum is σ = 5050555551404. Its totient is φ = 5050555551402.

The previous prime is 5050555551397. The next prime is 5050555551407. The reversal of 5050555551403 is 3041555550505.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5050555551403 - 2³³ = 5041965616811 is a prime.

It is a super-3 number, since 3×5050555551403³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 5050555551403.

It is not a weakly prime, because it can be changed into another prime (5050555551407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525277775701 + 2525277775702.

It is an arithmetic number, because the mean of its divisors is an integer number (2525277775702).

Almost surely, 2^{5050555551403} is an apocalyptic number.

5050555551403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5050555551403 is an equidigital number, since it uses as much as digits as its factorization.

5050555551403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 937500, while the sum is 43.

The spelling of 5050555551403 in words is "five trillion, fifty billion, five hundred fifty-five million, five hundred fifty-one thousand, four hundred three".