Base | Representation |
---|---|
bin | 1110101100110100100… |
… | …11100101101100100001 |
3 | 1210021202021202120001122 |
4 | 13112122103211230201 |
5 | 31233421100000113 |
6 | 1024012325542025 |
7 | 51330564106166 |
oct | 7263223455441 |
9 | 1707667676048 |
10 | 505100000033 |
11 | 185236866a62 |
12 | 81a84b74915 |
13 | 38827920185 |
14 | 1a6386b606d |
15 | d21373e408 |
hex | 759a4e5b21 |
505100000033 has 2 divisors, whose sum is σ = 505100000034. Its totient is φ = 505100000032.
The previous prime is 505100000003. The next prime is 505100000071. The reversal of 505100000033 is 330000001505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 389685565504 + 115414434529 = 624248^2 + 339727^2 .
It is a cyclic number.
It is not a de Polignac number, because 505100000033 - 28 = 505099999777 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 505099999957 and 505100000020.
It is not a weakly prime, because it can be changed into another prime (505100000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252550000016 + 252550000017.
It is an arithmetic number, because the mean of its divisors is an integer number (252550000017).
Almost surely, 2505100000033 is an apocalyptic number.
It is an amenable number.
505100000033 is a deficient number, since it is larger than the sum of its proper divisors (1).
505100000033 is an equidigital number, since it uses as much as digits as its factorization.
505100000033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225, while the sum is 17.
Adding to 505100000033 its reverse (330000001505), we get a palindrome (835100001538).
The spelling of 505100000033 in words is "five hundred five billion, one hundred million, thirty-three", and thus it is an aban number.
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