Base | Representation |
---|---|
bin | 1110101101000011100… |
… | …01010110101011000011 |
3 | 1210022002000102120120022 |
4 | 13112201301112223003 |
5 | 31234200130241311 |
6 | 1024033002204055 |
7 | 51333644466044 |
oct | 7264161265303 |
9 | 1708060376508 |
10 | 505225243331 |
11 | 1852a052a116 |
12 | 81abaab362b |
13 | 38847861833 |
14 | 1a64b1988cb |
15 | d21e72d5db |
hex | 75a1c56ac3 |
505225243331 has 2 divisors, whose sum is σ = 505225243332. Its totient is φ = 505225243330.
The previous prime is 505225243319. The next prime is 505225243409. The reversal of 505225243331 is 133342522505.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-505225243331 is a prime.
It is a super-2 number, since 2×5052252433312 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 505225243291 and 505225243300.
It is not a weakly prime, because it can be changed into another prime (505225243631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252612621665 + 252612621666.
It is an arithmetic number, because the mean of its divisors is an integer number (252612621666).
Almost surely, 2505225243331 is an apocalyptic number.
505225243331 is a deficient number, since it is larger than the sum of its proper divisors (1).
505225243331 is an equidigital number, since it uses as much as digits as its factorization.
505225243331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 505225243331 its reverse (133342522505), we get a palindrome (638567765836).
The spelling of 505225243331 in words is "five hundred five billion, two hundred twenty-five million, two hundred forty-three thousand, three hundred thirty-one".
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