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505261113121 is a prime number
BaseRepresentation
bin1110101101000111110…
…10001011111100100001
31210022011111220221200001
413112203322023330201
531234233321104441
61024040323100001
751334561412512
oct7264372137441
91708144827601
10505261113121
111853097a9676
1281b0ab11601
133885211046b
141a651c54a09
15d222966731
hex75a3e8bf21

505261113121 has 2 divisors, whose sum is σ = 505261113122. Its totient is φ = 505261113120.

The previous prime is 505261113113. The next prime is 505261113127. The reversal of 505261113121 is 121311162505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 374170773025 + 131090340096 = 611695^2 + 362064^2 .

It is a cyclic number.

It is not a de Polignac number, because 505261113121 - 23 = 505261113113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 505261113121.

It is not a weakly prime, because it can be changed into another prime (505261113127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252630556560 + 252630556561.

It is an arithmetic number, because the mean of its divisors is an integer number (252630556561).

Almost surely, 2505261113121 is an apocalyptic number.

It is an amenable number.

505261113121 is a deficient number, since it is larger than the sum of its proper divisors (1).

505261113121 is an equidigital number, since it uses as much as digits as its factorization.

505261113121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 28.

Adding to 505261113121 its reverse (121311162505), we get a palindrome (626572275626).

The spelling of 505261113121 in words is "five hundred five billion, two hundred sixty-one million, one hundred thirteen thousand, one hundred twenty-one".