Base | Representation |
---|---|
bin | 100100110001001000101… |
… | …1000000101110001000011 |
3 | 122220002111121010210100121 |
4 | 1021202101120011301003 |
5 | 1130243200030121431 |
6 | 14425244033001111 |
7 | 1031042664654052 |
oct | 111422130056103 |
9 | 18802447123317 |
10 | 5053320551491 |
11 | 1679112791043 |
12 | 69744a9b3197 |
13 | 2a86aba60754 |
14 | 1368210c2399 |
15 | 8b6ad878611 |
hex | 49891605c43 |
5053320551491 has 2 divisors, whose sum is σ = 5053320551492. Its totient is φ = 5053320551490.
The previous prime is 5053320551449. The next prime is 5053320551509. The reversal of 5053320551491 is 1941550233505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5053320551491 - 239 = 4503564737603 is a prime.
It is a super-2 number, since 2×50533205514912 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5053320551291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526660275745 + 2526660275746.
It is an arithmetic number, because the mean of its divisors is an integer number (2526660275746).
Almost surely, 25053320551491 is an apocalyptic number.
5053320551491 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053320551491 is an equidigital number, since it uses as much as digits as its factorization.
5053320551491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405000, while the sum is 43.
Adding to 5053320551491 its reverse (1941550233505), we get a palindrome (6994870784996).
The spelling of 5053320551491 in words is "five trillion, fifty-three billion, three hundred twenty million, five hundred fifty-one thousand, four hundred ninety-one".
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