Base | Representation |
---|---|
bin | 100100110001010101111… |
… | …0100010110100001000011 |
3 | 122220010122111212211110022 |
4 | 1021202223310112201003 |
5 | 1130300102111331442 |
6 | 14425400041124055 |
7 | 1031056662434651 |
oct | 111425364264103 |
9 | 18803574784408 |
10 | 5053764167747 |
11 | 1679320137549 |
12 | 69755348962b |
13 | 2a874c933889 |
14 | 136863d9bdd1 |
15 | 8b6d77a53d2 |
hex | 498abd16843 |
5053764167747 has 2 divisors, whose sum is σ = 5053764167748. Its totient is φ = 5053764167746.
The previous prime is 5053764167743. The next prime is 5053764167759. The reversal of 5053764167747 is 7477614673505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5053764167747 - 22 = 5053764167743 is a prime.
It is a super-3 number, since 3×50537641677473 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5053764167747.
It is not a weakly prime, because it can be changed into another prime (5053764167743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526882083873 + 2526882083874.
It is an arithmetic number, because the mean of its divisors is an integer number (2526882083874).
Almost surely, 25053764167747 is an apocalyptic number.
5053764167747 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053764167747 is an equidigital number, since it uses as much as digits as its factorization.
5053764167747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103723200, while the sum is 62.
The spelling of 5053764167747 in words is "five trillion, fifty-three billion, seven hundred sixty-four million, one hundred sixty-seven thousand, seven hundred forty-seven".
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