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50542430542433 is a prime number
BaseRepresentation
bin10110111110111110100111…
…00111100101101001100001
320121221210211212220212021222
423133133103213211221201
523111041344204324213
6255254512210224425
713434366355103024
oct1337372347455141
9217853755825258
1050542430542433
1115116a19448085
125803565885115
132228191343a9b
14c6a3a3b291bb
155c9ad0835808
hex2df7d39e5a61

50542430542433 has 2 divisors, whose sum is σ = 50542430542434. Its totient is φ = 50542430542432.

The previous prime is 50542430542271. The next prime is 50542430542447. The reversal of 50542430542433 is 33424503424505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30843994665169 + 19698435877264 = 5553737^2 + 4438292^2 .

It is a cyclic number.

It is not a de Polignac number, because 50542430542433 - 210 = 50542430541409 is a prime.

It is a super-2 number, since 2×505424305424332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (50542430562433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25271215271216 + 25271215271217.

It is an arithmetic number, because the mean of its divisors is an integer number (25271215271217).

Almost surely, 250542430542433 is an apocalyptic number.

It is an amenable number.

50542430542433 is a deficient number, since it is larger than the sum of its proper divisors (1).

50542430542433 is an equidigital number, since it uses as much as digits as its factorization.

50542430542433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456000, while the sum is 44.

Adding to 50542430542433 its reverse (33424503424505), we get a palindrome (83966933966938).

The spelling of 50542430542433 in words is "fifty trillion, five hundred forty-two billion, four hundred thirty million, five hundred forty-two thousand, four hundred thirty-three".