Base | Representation |
---|---|
bin | 10110111110111110100111… |
… | …00111100101101001100001 |
3 | 20121221210211212220212021222 |
4 | 23133133103213211221201 |
5 | 23111041344204324213 |
6 | 255254512210224425 |
7 | 13434366355103024 |
oct | 1337372347455141 |
9 | 217853755825258 |
10 | 50542430542433 |
11 | 15116a19448085 |
12 | 5803565885115 |
13 | 2228191343a9b |
14 | c6a3a3b291bb |
15 | 5c9ad0835808 |
hex | 2df7d39e5a61 |
50542430542433 has 2 divisors, whose sum is σ = 50542430542434. Its totient is φ = 50542430542432.
The previous prime is 50542430542271. The next prime is 50542430542447. The reversal of 50542430542433 is 33424503424505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30843994665169 + 19698435877264 = 5553737^2 + 4438292^2 .
It is a cyclic number.
It is not a de Polignac number, because 50542430542433 - 210 = 50542430541409 is a prime.
It is a super-2 number, since 2×505424305424332 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50542430562433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25271215271216 + 25271215271217.
It is an arithmetic number, because the mean of its divisors is an integer number (25271215271217).
Almost surely, 250542430542433 is an apocalyptic number.
It is an amenable number.
50542430542433 is a deficient number, since it is larger than the sum of its proper divisors (1).
50542430542433 is an equidigital number, since it uses as much as digits as its factorization.
50542430542433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456000, while the sum is 44.
Adding to 50542430542433 its reverse (33424503424505), we get a palindrome (83966933966938).
The spelling of 50542430542433 in words is "fifty trillion, five hundred forty-two billion, four hundred thirty million, five hundred forty-two thousand, four hundred thirty-three".
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