Base | Representation |
---|---|
bin | 100100110001100110001… |
… | …1111110100100110000011 |
3 | 122220012001201112122102201 |
4 | 1021203030133310212003 |
5 | 1130302212440342201 |
6 | 14425530304254031 |
7 | 1031106400555666 |
oct | 111431437644603 |
9 | 18805051478381 |
10 | 5054312434051 |
11 | 16795816700a1 |
12 | 697687011317 |
13 | 2a88093b7bca |
14 | 1368b6b196dd |
15 | 8b71a9a4801 |
hex | 498cc7f4983 |
5054312434051 has 2 divisors, whose sum is σ = 5054312434052. Its totient is φ = 5054312434050.
The previous prime is 5054312434037. The next prime is 5054312434079. The reversal of 5054312434051 is 1504342134505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5054312434051 - 27 = 5054312433923 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5054312434051.
It is not a weakly prime, because it can be changed into another prime (5054312434001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527156217025 + 2527156217026.
It is an arithmetic number, because the mean of its divisors is an integer number (2527156217026).
Almost surely, 25054312434051 is an apocalyptic number.
5054312434051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5054312434051 is an equidigital number, since it uses as much as digits as its factorization.
5054312434051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 5054312434051 its reverse (1504342134505), we get a palindrome (6558654568556).
The spelling of 5054312434051 in words is "five trillion, fifty-four billion, three hundred twelve million, four hundred thirty-four thousand, fifty-one".
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