Base | Representation |
---|---|
bin | 10110111111000000010001… |
… | …01101100111000100100011 |
3 | 20121221220010222001201120121 |
4 | 23133200020231213010203 |
5 | 23111100210224013241 |
6 | 255255140430421111 |
7 | 13434430422403312 |
oct | 1337401055470443 |
9 | 217856128051517 |
10 | 50543321313571 |
11 | 15117336246679 |
12 | 5803774061797 |
13 | 22282a3a588b8 |
14 | c6a44a162279 |
15 | 5c9b33b3cad1 |
hex | 2df808b67123 |
50543321313571 has 2 divisors, whose sum is σ = 50543321313572. Its totient is φ = 50543321313570.
The previous prime is 50543321313517. The next prime is 50543321313581. The reversal of 50543321313571 is 17531312334505.
Together with previous prime (50543321313517) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50543321313571 is a prime.
It is not a weakly prime, because it can be changed into another prime (50543321313581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25271660656785 + 25271660656786.
It is an arithmetic number, because the mean of its divisors is an integer number (25271660656786).
Almost surely, 250543321313571 is an apocalyptic number.
50543321313571 is a deficient number, since it is larger than the sum of its proper divisors (1).
50543321313571 is an equidigital number, since it uses as much as digits as its factorization.
50543321313571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 567000, while the sum is 43.
The spelling of 50543321313571 in words is "fifty trillion, five hundred forty-three billion, three hundred twenty-one million, three hundred thirteen thousand, five hundred seventy-one".
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