Base | Representation |
---|---|
bin | 100100110001111111001… |
… | …1010111011001100001011 |
3 | 122220021020002120222012122 |
4 | 1021203332122323030023 |
5 | 1130310421400324042 |
6 | 14430145344401455 |
7 | 1031136221056505 |
oct | 111437632731413 |
9 | 18807202528178 |
10 | 5055150011147 |
11 | 1679971437175 |
12 | 69787b61628b |
13 | 2a8910a96862 |
14 | 136956066d75 |
15 | 8b7692a07d2 |
hex | 498fe6bb30b |
5055150011147 has 2 divisors, whose sum is σ = 5055150011148. Its totient is φ = 5055150011146.
The previous prime is 5055150011129. The next prime is 5055150011179. The reversal of 5055150011147 is 7411100515505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5055150011147 - 26 = 5055150011083 is a prime.
It is not a weakly prime, because it can be changed into another prime (5055150011447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527575005573 + 2527575005574.
It is an arithmetic number, because the mean of its divisors is an integer number (2527575005574).
Almost surely, 25055150011147 is an apocalyptic number.
5055150011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5055150011147 is an equidigital number, since it uses as much as digits as its factorization.
5055150011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17500, while the sum is 35.
The spelling of 5055150011147 in words is "five trillion, fifty-five billion, one hundred fifty million, eleven thousand, one hundred forty-seven".
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