Base | Representation |
---|---|
bin | 101111000101001000… |
… | …100100111010000011 |
3 | 11211111001111200110011 |
4 | 233011020210322003 |
5 | 1312012303001011 |
6 | 35120120445351 |
7 | 3436503624403 |
oct | 570510447203 |
9 | 154431450404 |
10 | 50552000131 |
11 | 1a491316a06 |
12 | 9969919857 |
13 | 49c8230719 |
14 | 2637b80803 |
15 | 14ad080621 |
hex | bc5224e83 |
50552000131 has 2 divisors, whose sum is σ = 50552000132. Its totient is φ = 50552000130.
The previous prime is 50552000123. The next prime is 50552000143. The reversal of 50552000131 is 13100025505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50552000131 - 23 = 50552000123 is a prime.
It is a super-2 number, since 2×505520001312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50552000831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25276000065 + 25276000066.
It is an arithmetic number, because the mean of its divisors is an integer number (25276000066).
Almost surely, 250552000131 is an apocalyptic number.
50552000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
50552000131 is an equidigital number, since it uses as much as digits as its factorization.
50552000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 750, while the sum is 22.
Adding to 50552000131 its reverse (13100025505), we get a palindrome (63652025636).
The spelling of 50552000131 in words is "fifty billion, five hundred fifty-two million, one hundred thirty-one", and thus it is an aban number.
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