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505534310401 is a prime number
BaseRepresentation
bin1110101101101000011…
…00010110100000000001
31210022212112222210212211
413112310030112200001
531240313240413101
61024123402422121
751344416511161
oct7266414264001
91708775883784
10505534310401
11185439a3684a
1281b86501941
13388968b5663
141a67a24c5a1
15d23b92dc51
hex75b4316801

505534310401 has 2 divisors, whose sum is σ = 505534310402. Its totient is φ = 505534310400.

The previous prime is 505534310383. The next prime is 505534310441. The reversal of 505534310401 is 104013435505.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 412518460176 + 93015850225 = 642276^2 + 304985^2 .

It is a cyclic number.

It is not a de Polignac number, because 505534310401 - 211 = 505534308353 is a prime.

It is a super-2 number, since 2×5055343104012 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (505534310441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252767155200 + 252767155201.

It is an arithmetic number, because the mean of its divisors is an integer number (252767155201).

Almost surely, 2505534310401 is an apocalyptic number.

It is an amenable number.

505534310401 is a deficient number, since it is larger than the sum of its proper divisors (1).

505534310401 is an equidigital number, since it uses as much as digits as its factorization.

505534310401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 505534310401 its reverse (104013435505), we get a palindrome (609547745906).

The spelling of 505534310401 in words is "five hundred five billion, five hundred thirty-four million, three hundred ten thousand, four hundred one".