Base | Representation |
---|---|
bin | 10110111111010110110101… |
… | …01001100001011000010001 |
3 | 20122000001102002002001010101 |
4 | 23133223122221201120101 |
5 | 23111300011422013013 |
6 | 255304502342332401 |
7 | 13435336524355252 |
oct | 1337533251413021 |
9 | 218001362061111 |
10 | 50555433391633 |
11 | 15121491199145 |
12 | 5805b9442a101 |
13 | 22294841a25b1 |
14 | c6ac789d6b29 |
15 | 5ca0e214b8dd |
hex | 2dfadaa61611 |
50555433391633 has 2 divisors, whose sum is σ = 50555433391634. Its totient is φ = 50555433391632.
The previous prime is 50555433391613. The next prime is 50555433391651. The reversal of 50555433391633 is 33619333455505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40162727483649 + 10392705907984 = 6337407^2 + 3223772^2 .
It is a cyclic number.
It is not a de Polignac number, because 50555433391633 - 233 = 50546843457041 is a prime.
It is not a weakly prime, because it can be changed into another prime (50555433391613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25277716695816 + 25277716695817.
It is an arithmetic number, because the mean of its divisors is an integer number (25277716695817).
Almost surely, 250555433391633 is an apocalyptic number.
It is an amenable number.
50555433391633 is a deficient number, since it is larger than the sum of its proper divisors (1).
50555433391633 is an equidigital number, since it uses as much as digits as its factorization.
50555433391633 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32805000, while the sum is 55.
The spelling of 50555433391633 in words is "fifty trillion, five hundred fifty-five billion, four hundred thirty-three million, three hundred ninety-one thousand, six hundred thirty-three".
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