Base | Representation |
---|---|
bin | 10110111111010110111101… |
… | …01001100001011011111011 |
3 | 20122000001120202100112111112 |
4 | 23133223132221201123323 |
5 | 23111300131112010411 |
6 | 255304513140550535 |
7 | 13435341300651512 |
oct | 1337533651413373 |
9 | 218001522315445 |
10 | 50555500500731 |
11 | 15121516065206 |
12 | 5805bb29b244b |
13 | 222949506b315 |
14 | c6ac838a5679 |
15 | 5ca0e7ea5b8b |
hex | 2dfadea616fb |
50555500500731 has 2 divisors, whose sum is σ = 50555500500732. Its totient is φ = 50555500500730.
The previous prime is 50555500500719. The next prime is 50555500500773. The reversal of 50555500500731 is 13700500555505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50555500500731 - 230 = 50554426758907 is a prime.
It is a super-2 number, since 2×505555005007312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50555500503731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25277750250365 + 25277750250366.
It is an arithmetic number, because the mean of its divisors is an integer number (25277750250366).
Almost surely, 250555500500731 is an apocalyptic number.
50555500500731 is a deficient number, since it is larger than the sum of its proper divisors (1).
50555500500731 is an equidigital number, since it uses as much as digits as its factorization.
50555500500731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 328125, while the sum is 41.
The spelling of 50555500500731 in words is "fifty trillion, five hundred fifty-five billion, five hundred million, five hundred thousand, seven hundred thirty-one".
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