Base | Representation |
---|---|
bin | 100100110010001011011… |
… | …1101000011100011001111 |
3 | 122220022021210002102201002 |
4 | 1021210112331003203033 |
5 | 1130312242233031341 |
6 | 14430254250410515 |
7 | 1031152346444450 |
oct | 111442675034317 |
9 | 18808253072632 |
10 | 5055561611471 |
11 | 167a062805628 |
12 | 697975430a3b |
13 | 2a897813a247 |
14 | 1369949ab127 |
15 | 8b7904a629b |
hex | 49916f438cf |
5055561611471 has 4 divisors (see below), whose sum is σ = 5777784698832. Its totient is φ = 4333338524112.
The previous prime is 5055561611467. The next prime is 5055561611473. The reversal of 5055561611471 is 1741161655505.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5055561611471 - 22 = 5055561611467 is a prime.
It is a super-3 number, since 3×50555616114713 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5055561611473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 361111543670 + ... + 361111543683.
It is an arithmetic number, because the mean of its divisors is an integer number (1444446174708).
Almost surely, 25055561611471 is an apocalyptic number.
5055561611471 is a deficient number, since it is larger than the sum of its proper divisors (722223087361).
5055561611471 is an equidigital number, since it uses as much as digits as its factorization.
5055561611471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 722223087360.
The product of its (nonzero) digits is 630000, while the sum is 47.
The spelling of 5055561611471 in words is "five trillion, fifty-five billion, five hundred sixty-one million, six hundred eleven thousand, four hundred seventy-one".
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