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50605505536753 is a prime number
BaseRepresentation
bin10111000000110100000110…
…01011100110001011110001
320122011211122200122120020201
423200122003023212023301
523113110033404134003
6255343503122235201
713442061413520526
oct1340320313461361
9218154580576221
1050605505536753
1115140746657962
1258138294b5b01
132231103b8232b
14c6d468b4714d
155cb572ee2b1d
hex2e06832e62f1

50605505536753 has 2 divisors, whose sum is σ = 50605505536754. Its totient is φ = 50605505536752.

The previous prime is 50605505536711. The next prime is 50605505536799. The reversal of 50605505536753 is 35763550550605.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50184586155664 + 420919381089 = 7084108^2 + 648783^2 .

It is a cyclic number.

It is not a de Polignac number, because 50605505536753 - 245 = 15421133447921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50605505536694 and 50605505536703.

It is not a weakly prime, because it can be changed into another prime (50605505576753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25302752768376 + 25302752768377.

It is an arithmetic number, because the mean of its divisors is an integer number (25302752768377).

Almost surely, 250605505536753 is an apocalyptic number.

It is an amenable number.

50605505536753 is a deficient number, since it is larger than the sum of its proper divisors (1).

50605505536753 is an equidigital number, since it uses as much as digits as its factorization.

50605505536753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35437500, while the sum is 55.

The spelling of 50605505536753 in words is "fifty trillion, six hundred five billion, five hundred five million, five hundred thirty-six thousand, seven hundred fifty-three".