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5061588299561 is a prime number
BaseRepresentation
bin100100110100111111000…
…1011000010111100101001
3122220212211210100220120002
41021221332023002330221
51130412113101041221
614433132255312345
71031454606445613
oct111517613027451
918825753326502
105061588299561
111681675704592
12698b7781b6b5
132a93c88bb681
14136da7165db3
158b9e461180b
hex49a7e2c2f29

5061588299561 has 2 divisors, whose sum is σ = 5061588299562. Its totient is φ = 5061588299560.

The previous prime is 5061588299497. The next prime is 5061588299567. The reversal of 5061588299561 is 1659928851605.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3739447075225 + 1322141224336 = 1933765^2 + 1149844^2 .

It is a cyclic number.

It is not a de Polignac number, because 5061588299561 - 26 = 5061588299497 is a prime.

It is a super-3 number, since 3×50615882995613 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (5061588299567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2530794149780 + 2530794149781.

It is an arithmetic number, because the mean of its divisors is an integer number (2530794149781).

Almost surely, 25061588299561 is an apocalyptic number.

It is an amenable number.

5061588299561 is a deficient number, since it is larger than the sum of its proper divisors (1).

5061588299561 is an equidigital number, since it uses as much as digits as its factorization.

5061588299561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656000, while the sum is 65.

The spelling of 5061588299561 in words is "five trillion, sixty-one billion, five hundred eighty-eight million, two hundred ninety-nine thousand, five hundred sixty-one".