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50645436313 is a prime number
BaseRepresentation
bin101111001010101101…
…000000011110011001
311211201120022201210111
4233022231000132121
51312210212430223
635133255244321
73442020051163
oct571255003631
9154646281714
1050645436313
111a52a03499a
1299950796a1
134a116b66c4
142646343933
1514b638a30d
hexbcab40799

50645436313 has 2 divisors, whose sum is σ = 50645436314. Its totient is φ = 50645436312.

The previous prime is 50645436299. The next prime is 50645436451. The reversal of 50645436313 is 31363454605.

50645436313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41187484809 + 9457951504 = 202947^2 + 97252^2 .

It is a cyclic number.

It is not a de Polignac number, because 50645436313 - 29 = 50645435801 is a prime.

It is not a weakly prime, because it can be changed into another prime (50645436713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25322718156 + 25322718157.

It is an arithmetic number, because the mean of its divisors is an integer number (25322718157).

Almost surely, 250645436313 is an apocalyptic number.

It is an amenable number.

50645436313 is a deficient number, since it is larger than the sum of its proper divisors (1).

50645436313 is an equidigital number, since it uses as much as digits as its factorization.

50645436313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 40.

The spelling of 50645436313 in words is "fifty billion, six hundred forty-five million, four hundred thirty-six thousand, three hundred thirteen".