Base | Representation |
---|---|
bin | 1110101111101010011… |
… | …00111010010001111001 |
3 | 1210102200120021100210202 |
4 | 13113311030322101321 |
5 | 31300031443212433 |
6 | 1024423523251545 |
7 | 51413432146223 |
oct | 7276514722171 |
9 | 1712616240722 |
10 | 506624975993 |
11 | 185949655a74 |
12 | 8222b819bb5 |
13 | 38a0b848706 |
14 | 1a74103b413 |
15 | d2a256dee8 |
hex | 75f533a479 |
506624975993 has 2 divisors, whose sum is σ = 506624975994. Its totient is φ = 506624975992.
The previous prime is 506624975947. The next prime is 506624976001. The reversal of 506624975993 is 399579426605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 334041229369 + 172583746624 = 577963^2 + 415432^2 .
It is a cyclic number.
It is not a de Polignac number, because 506624975993 - 210 = 506624974969 is a prime.
It is not a weakly prime, because it can be changed into another prime (506624975093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253312487996 + 253312487997.
It is an arithmetic number, because the mean of its divisors is an integer number (253312487997).
Almost surely, 2506624975993 is an apocalyptic number.
It is an amenable number.
506624975993 is a deficient number, since it is larger than the sum of its proper divisors (1).
506624975993 is an equidigital number, since it uses as much as digits as its factorization.
506624975993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110224800, while the sum is 65.
The spelling of 506624975993 in words is "five hundred six billion, six hundred twenty-four million, nine hundred seventy-five thousand, nine hundred ninety-three".
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