Base | Representation |
---|---|
bin | 1110101111101011100… |
… | …00001011100110110001 |
3 | 1210102201012200002221111 |
4 | 13113311300023212301 |
5 | 31300041330101001 |
6 | 1024424453353321 |
7 | 51413603555425 |
oct | 7276560134661 |
9 | 1712635602844 |
10 | 506634222001 |
11 | 1859538a06a6 |
12 | 82232938841 |
13 | 38a1073501b |
14 | 1a742366b85 |
15 | d2a3298851 |
hex | 75f5c0b9b1 |
506634222001 has 2 divisors, whose sum is σ = 506634222002. Its totient is φ = 506634222000.
The previous prime is 506634221983. The next prime is 506634222013. The reversal of 506634222001 is 100222436605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 506459955600 + 174266401 = 711660^2 + 13201^2 .
It is a cyclic number.
It is not a de Polignac number, because 506634222001 - 215 = 506634189233 is a prime.
It is a super-3 number, since 3×5066342220013 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (506634222041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253317111000 + 253317111001.
It is an arithmetic number, because the mean of its divisors is an integer number (253317111001).
Almost surely, 2506634222001 is an apocalyptic number.
It is an amenable number.
506634222001 is a deficient number, since it is larger than the sum of its proper divisors (1).
506634222001 is an equidigital number, since it uses as much as digits as its factorization.
506634222001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 506634222001 its reverse (100222436605), we get a palindrome (606856658606).
The spelling of 506634222001 in words is "five hundred six billion, six hundred thirty-four million, two hundred twenty-two thousand, one".
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